# Question #59964

Sep 24, 2016

$\text{The electronic configuration of oxygen } \to 1 {s}^{2} \textcolor{red}{2 {s}^{2} 2 {p}_{x}^{2}} 2 {p}_{y}^{1} 2 {p}_{z}^{1}$
The Oxygen atom has two unpaired and two lone pairs of electrons in the valence shell.The two unpaired electrons form two $\sigma$-bond with two C-atoms of two $C {H}_{3}$ group leaving behind two lone pairs of electrons.