# Question #a1d99

Dec 19, 2016

Impossible

#### Explanation:

We 'assume' that n is an integer. This means 2n is always an even integer.
The left hand side term is $- {1}^{2 n}$ this is always equal to 1.
Or if we read the left hand term differently as $- \left({1}^{2 n}\right)$, then the term is always -1.
The right hand term is ${1}^{3}$ + ${5}^{8}$ which is way bigger than 1 or -1
So in both interpretations of -1^2n the question has no solution for n.

Am I missing something here?