If the rate of change in #x# is #"3 s"^(-1)#, and #(dy)/(dx) = 5#, what is the rate of change in #y#? Is #y# changing faster than #x# or vice versa?

1 Answer
Sep 25, 2016

The rate of change, or derivative, of #y# with respect to #x# can be written as

#(dy)/(dx) = 5#,

or

#dy = 5dx#.

We can say that on a non-infinitesimally-small scale,

#Deltay# #~~# #5Deltax#.

Therefore, if #x# changes as #"3 s"^(-1)#, then we let #Deltax = 3#, and

#Deltay = 5xx3 = "15 s"^(-1) > Deltax#,

and we have that #color(blue)(Deltay > Deltax)#.

This means #y# is changing faster than #x#, if we assume that the change in #x# does not itself change, and the change in #y# does not itself change either.