Question

Question #d2c06

Answer 1

1. `x = 4`
2. `x>6.25`
3. `x=-10`
4. ...
5. `-2x^2+3x+9`
6. ..

Explanation:

• `3*x+5 = 17`
  To solve these of equations, the unknown, `x`, has to be isolated one side of the equation,
  First, we subtract 5 from both side of the equation to get rid of the 5 on the left side.
  `3*x +5 -5 = 17 -5`
  `3*x = 12`

Then divide by 3 both sides
`(3*x)/3 = 12/3`
`x = 4`
(3 by 3 cancel out, and 12/3=4)

• `4*x- 5>20`

Same as before, add 5 to both sides of the equation
`4*x- 5+5>20+5`
`4*x>25`

divide by 4 both sides of the equation
`(4*x)/4>25/4`
`x>6 1/4`
`x>6.25`

• `2-x=12`
  subtract 2 from both sides of the equation
  `2-x-2=12-2`
  `-x=10`
  since x is negative, we have to multiply both sides by -1
  `(-x)(-1)=(10)(-1)`
  `x=-10`

• 4th try it yourself

• `(2x+3)(3-x)`
  in these kind of equations, you have to multiply each term of the first with the each terms of the second,
  it is written as `(ax+b)*(cx+d)`
  and it is equal to
  `(ax)(cx)+(b)(cx)+(ax)(d)+(b)(d)`

in the one in your example,
`(2x+3)(3-x)`
is equal to
`(2x)(-x)+(3)(-x)+(2x)(3)+(3)(3)=-2x^2+(-3x)+6x+9`
simplifying the answer by adding `-3x+6x=3x`
Therefore, the answer is
=`-2x^2+3x+9`

• Last one give it a try

If you could not solve the 4th and the last I will help you with them.
I Hope that this will help. :)