How do you divide? #(x^3 + y^3) div(x-y)#

1 Answer
Sep 26, 2016

Answer:

#(x^3 + y^3) div(x-y) = x^2 +xy +y^2 " rem " 2y^3#

Explanation:

We can do it by algebraic long division:

#"dividend"/"divisor" = "quotient"#

  1. Write the dividend in the 'box' making sure that the indices are in descending powers of x. Make spaces for any missing terms.

  2. Divide the first term in the divisor into the term in the dividend with the highest index. Write the answer at the top,

  3. Multiply by BOTH terms of the divisor at the side

  4. Subtract

  5. Bring down the next term

Repeat steps 2 to 5

#color(white)(xxxxxx.xxxxxx)color(red)(x^2)" " color(blue)(+xy)" "+color(lime)(y^2) " rem "2y^3 #
#color(white)(xxx)x-y |bar( x^3 +0x^2y+0xy^2 +y^3" "larrx^3divx =color(red)(x^2#
#color(white)(xxxxx)-(ul(color(red)(x^3-x^2y)))" "larr# subtract
#color(white)(xxxxxxxxxx) +x^2y" "larrx^2y div x = color(blue)(xy)#
#color(white)(xxxxxx.x.)-(ul(color(blue)(x^2y-xy^2)))color(white)(x)darr" "larr# subtract
#color(white)(xxxxxxxxxxx.x.xxx)xy^2 -y^3 " "larrxy^2divx = color(lime)(y^2)#
#color(white)(xxxxxxxx..x.xxx)ul(-color(lime)((xy^2 +y^3)) " "larr# subtract
#color(white)(xxxxxxxxxxxxxxxxxxxx)2y^3larr" "# remainder

#(x^3 + y^3) div(x-y) = x^2 +xy +y^2 " rem " 2y^3#