Question #4e641

1 Answer
Sep 29, 2016

This is an odd function.

Explanation:

To check if a function #f(x)# is odd or even (or neither) you have to calculate #f(-x)# and compare the calculated value with #f(x)#.

  • If #f(-x)=f(x)# then #f(x)# is even,

  • if #f(-x)=-f(x)# then #f(x)# is odd.

Here we have:

#f(x)=x^3+7x#

#f(-x)=(-x)^3+7*(-x)#

#f(-x)=-x^3-7x#

We see that the value is an opposite expression to #f(x)#.

#f(-x)=-f(x)#, so the function is odd

Other way to see if the function is even or odd is to look at the function's graph.

  • if the graph is symetrical according to #Y# axis then the function is even.Example: #y=x^2+2#

graph{x^2+2 [-10, 10, -5, 5]}

  • If the graph is symetrical according to the origin #(0,0)# then it is odd. Example: #x^3+7x#

graph{x^3+7x [-3, 3, -50, 50]}