Assuming the question is to find the equation of the line passing through those two points:
Step 1: Find the slope of the line
The slope mm of a line passing through the points (x_1, y_1)(x1,y1) and (x_2, y_2)(x2,y2) is given by
m = (y_2-y_1)/(x_2-x_1)m=y2−y1x2−x1
Substituting the given points in, we get
m = (7 - 0)/(9 - (-3)) = 7/12m=7−09−(−3)=712
Step 2: Write the equation of the line in point-slope form
The point-slope form of a line with slope mm and passing through the point (x_1, y_1)(x1,y1) is
y - y_1 = m(x-x_1)y−y1=m(x−x1)
Substituting one of the given points and our slope, we get
y - 0 = 7/12(x - (-3))y−0=712(x−(−3))
=> y = 7/12(x+3)⇒y=712(x+3)
Step 3: Convert the equation into standard form
The standard form of a line is Ax + By = CAx+By=C where, if possible, A,B,A,B, and CC are integers without a common factor. We perform algebraic manipulations on the above equation until it matches this form.
y = 7/12(x+3)y=712(x+3)
=> y = 7/12x + 7/4⇒y=712x+74
=> -7/12x + y = 7/4⇒−712x+y=74
:.-7x + 12y = 21
