Question #2c645

Question

Question #2c645

1 Answer

Impact of this question

1294 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-03T14:13:50

$n = 637$ $n=637$

Explanation:

We know that $5^{5} = 3125 > 2557$ $5^5=3125 > 2557$ so the number of trailing zeroes is given by

$n = 4 \sum k = 1 ⌊ \frac{2557}{5^{k}} ⌋ = 511 + 102 + 20 + 4 = 637$ $n=sum_(k=1)^4 floor(2557/5^k) = 511+102+20+4=637$

which is the number of $5$ $5$ factors appearing in $2557$ $2557$ Those $5$ $5$ multiplied by the $2$ $2$ factors are responsible by the trailing zeroes.

Science

Math

Humanities

... and beyond

Question #2c645

1 Answer

Explanation:

Related questions

Impact of this question