# Question a32d8

Oct 1, 2016

You are to determine the number of molecules of $N {H}_{3}$ .

One molecule of $N {H}_{3}$ contains 3 atoms of Hydrogen.So to produce one mole of $N {H}_{3}$ we require $\frac{3}{2} m o l {H}_{2}$ The following equation also supports that

${N}_{2} + 3 {H}_{2} \to 2 N {H}_{3}$

So 1 mole ${H}_{2}$ produces $\frac{2}{3} m o l N {H}_{3}$
Hydrogen taken $= 7.98 \times {10}^{-} 4 g$

$= 1.64 \times {10}^{-} 4 g \times \frac{1}{2.016 \frac{g}{\text{mol}}}$

where molar mass of Hydrogen $= 2.016 \frac{g}{\text{mol}}$

So no.of moles of $N {H}_{3}$ produced
$= \frac{2}{3} \times 1.64 \times {10}^{-} 4 g \times \frac{1}{2.016 \frac{g}{\text{mol}}}$

So no.of molecules of $N {H}_{3}$ produced

=2/3xx1.64xx10^-4gxx1/(2.016g/"mol")xx6.023xx10^23"molecule"/"mol"#
$\approx 3.27 \times {10}^{19}$molecules