# Question #2cd38

Jan 17, 2018

As I understood

#### Explanation:

Let $\vec{A} = {A}_{x} \hat{i} + {A}_{y} \hat{j} + {A}_{z} \hat{k}$ and
$\vec{B} = {B}_{x} \hat{i} + {B}_{y} \hat{j} + {B}_{z} \hat{k}$

To find ($\vec{A} - \vec{B}$)
Inserting values of both the vectors in terms of unit vectors we get

$\vec{A} - \vec{B} = \left({A}_{x} \hat{i} + {A}_{y} \hat{j} + {A}_{z} \hat{k}\right) - \left({B}_{x} \hat{i} + {B}_{y} \hat{j} + {B}_{z} \hat{k}\right)$
$\implies \vec{A} - \vec{B} = \left({A}_{x} - {B}_{x}\right) \hat{i} + \left({A}_{y} - {B}_{y}\right) \hat{j} + \left({A}_{z} - {B}_{z}\right) \hat{k}$