# Question 79071

Jan 3, 2017

1.2xx10^3 J"#

#### Explanation:

The kinetic energy of the steel ball can be obtained via the following equation:

Additionally, the kinetic energy will have units of $k g \times {m}^{2} / {s}^{2}$, which is the same as Joules, J.

We already have the mass and velocity, and both have the correct units so all we have to do is plug the given values into the equation:

$K E = \left(\frac{1}{2}\right) \left(7.3 k g\right) {\left(18.0 \frac{m}{s}\right)}^{2}$
$K E = 1.2 \times {10}^{3} k g \times {m}^{2} / {s}^{2}$

$K E = 1.2 \times {10}^{3} J$