Question

Question #b8942

Answer 1

Given
`vec(X)+vec(Y)=vec(R)`

So `vec(X)+vec(Y)+vec(Z)=vec(R)+vec(Z)`

Ler the angle between `vec(Z) and vec(R)` be `theta=170^@`

Also given `abs(vec(Z))=13.5N and abs(vec(R))=19.3N`

Now `abs(vec(X)+vec(Y)+vec(Z))= abs(vec(Z)+vec(R))`

`=sqrt(abs(vec(Z))^2+ abs(vec(R))^2+2abs(vec(Z))*abs(vec(R))costheta)`

`=sqrt((13.5)^2+ (19.3)^2+2*13.5*(19.3)*cos170)`
`=6.45N`