Question #8ffa7

1 Answer
Noah G
Oct 14, 2016

Just expand the factorials.

(n + 1)(n) + (n + 1)(n) xx n+ 1 = (n + 2)(n + 1)(n)

n^2 + n + (n^2 + n)(n + 1) = (n^2 + 3n + 2)(n)

n^2 + n + n^3+ n^2 + n^2 + n = n^3 + 3n^2 + 2n

n^3 + 3n^2 + 2n = n^3 + 3n^2 + 2n

Hopefully this helps!

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