# Question #ee354

Oct 14, 2016

Molar mass of Hydrogen$= 2 \text{ g/mol}$
Amount of Hydrogen to be produced

$= 10 g = \frac{10 g}{2 \frac{g}{\text{mol}}} = 5 m o l$

Reaction used

$Z n + 2 H N {O}_{3} \to Z n {\left(N {O}_{3}\right)}_{2} + {H}_{2}$

This equation reveals that 1 mol Hydrogen is produced if 2 mol $H N {O}_{3}$ is reacted with excess Zn.

To produce 10g or 5 mol ${H}_{2}$ we require $5 \times 2 = 10 \text{ mol } H N {O}_{3}$

This amount of $H N {O}_{3}$ can be obtained from 2M solution having volume $V = \frac{10 m o l}{2 \frac{\text{mol}}{L}} = 5 L$