# A mass of 30*g of KNO_3 was dissolved in water to give a 0.30*mol*L^-1 solution. What volume of water was used?

Jan 7, 2018

Approx. $1 \cdot L$

#### Explanation:

We use the relationship...

$\text{Concentration"="Moles of solute"/"Volume of solution....}$

And thus we get .....$\text{Volume of solution"="Moles of solute"/"Concentration}$

$= \frac{\frac{30.0 \cdot g}{101.1 \cdot g \cdot m o {l}^{-} 1}}{0.30 \cdot m o l \cdot {L}^{-} 1} = 1.00 \cdot \frac{1}{L} ^ - 1 = \frac{1}{\frac{1}{L}} = 1.00 \cdot L$