# Question #bc73c

##### 1 Answer

We know that

so the function is continuous at

I don't have a way to evaluate this limit without l'Hopital's Rule, so I hope you have it to work with. ( **See edit below.** )

So the initial form of

This is an indeterminate form to which we can apply l'Hopital's Rule.

Yes,

**Edit I do have a way to evaluate this without l"Hopital**

With

Therefore

Back to the main question

# = lim_(xrarr0) (arctanx/x) * lim_(xrarr0)(x/sinx)#

# = (1)(1)=1#