# Question #0733f

Use the following ${\cos}^{2} x + {\sin}^{2} = 1$
So $1 - {\cos}^{2} x = {\sin}^{2} x$
and $\cot x = \cos \frac{x}{\sin} x$
$\left(1 - {\cos}^{2} x\right) \cot x = {\sin}^{2} x \cdot \cos \frac{x}{\sin} x = \sin x \cos x$