# Question #23976

##### 1 Answer
Oct 24, 2016

$\left(0 , - \frac{1}{2}\right)$

#### Explanation:

Given the coordinate points $\left({x}_{1} , {y}_{1}\right) \text{ and } \left({x}_{2} , {y}_{2}\right)$ then the coordinates of the midpoint $\left({x}_{m} , {y}_{m}\right)$ are found as follows.

${x}_{m} = \frac{1}{2} \left({x}_{1} + {x}_{2}\right) \text{ the average of the x-coordinates}$

and ${y}_{m} = \frac{1}{2} \left({y}_{1} + {y}_{2}\right) \text{ the average of the y-coordinates}$

here $\left({x}_{1} , {y}_{1}\right) = \left(- 1 , 2\right) \text{ and } \left({x}_{2} , {y}_{2}\right) = \left(1 , - 3\right)$

$\Rightarrow {x}_{m} = \frac{1}{2} \left(- 1 + 1\right) = 0$

and ${y}_{m} = \frac{1}{2} \left(2 - 3\right) = - \frac{1}{2}$

Hence coordinates of midpoint $= \left(0 , - \frac{1}{2}\right)$