# Question #f6853

Molar mass of $M g S {O}_{4} = 24 + 32 + 4 \cdot 16 = 120 \text{ g/mol}$
$7.5 \times {10}^{2} m L \mathmr{and} 0.75 L \text{ "0.000450M" } M g S {O}_{4}$ solution contains $0.75 \times 4.5 \times {10}^{-} 4 m o l \text{ } M g S {O}_{4}$
$= 3.375 \times {10}^{-} 4 m o l \times 120 \frac{g}{\text{mol"=4.05xx10^-2g " }} M g S {O}_{4}$
$= 40.5 m g \text{ } M g S {O}_{4}$
So $4.05 m g \text{ } M g S {O}_{4}$ is to be taken taken in a 750mL volumetric flask and after dissolving it in water volume is made up to 750mL by adding water.