# Question #197e4

Nov 4, 2016

Calculate the concentration of ${H}^{+}$ and then take the negative base-10 logarithm to get the pH.

#### Explanation:

The balanced reaction is
$C {H}_{3} C O O H \left(a q\right) \leftrightarrow {H}^{+} \left(a q\right) + C {H}_{3} C O {O}^{-} \left(a q\right)$

If 5% of the acid ionizes, then the concentration of ${H}^{+}$ is
$\left[{H}^{+}\right] = 2.0 M \times 0.05 = 0.1 M$

The ph is then

pH = $- \log \left[{H}^{+}\right] = - \log \left(0.1\right) = 1.0$