Question #f0f5a

2 Answers
Nov 14, 2016

dy/dx=(1/ysec^2(x/y))/(1+x/y^2sec^2(x/y))

Explanation:

sec^2(x/y)*(y-dy/dxx)/y^2=dy/dx

Nov 14, 2016

(1+y^2)/(y+(1+y^2)tan^(-1)y)

Explanation:

You can try this differentiation, instead.

Solving for x,

x = y tan^(-1)y

(dx)/(dy)=tan^(-1)y+y/(1+y^2).

y'=1/((dx)/(dy))=(1+y^2)/(y+(1+y^2)tan^(-1)y)