Question #7ce5f

1 Answer
Apr 11, 2017

For part a. see below.

Explanation:

Given: #sin theta = -5/13# and #(3pi)/2 < theta < 2pi#

We know that #sin^2theta+cos^theta=1# for all #theta#

Since #(3pi)/2 < theta < 2pi#, we see that #cos theta > 0#

Therefore,

#costheta = sqrt(1-sin^2theta) = sqrt (144/169) = 12/13#

Now we have

#sin theta = -5/13# and #costheta = 12/13#

The other values can be found using these two.

#tan theta = sintheta/costheta = -5/12#

#csc theta = 1/sintheta = -13/5#

#sectheta = 1/costheta = 13/12#

#cot theta = costheta/sintheta = -12/5#