Question #aadaa

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Answer 1 · 2016-11-08T17:45:35

see below

#(cscx+secx)/(sinx+cosx)=cscx/cosx#

Left Side: #=(cscx+secx)/(sinx+cosx)#

#=(1/sinx+1/cosx)/(sinx+cosx)#

#=((cosx+sinx)/(sinxcosx))/(sinx+cosx)#

#=cancel (cosx+sinx)/(sinxcosx) * 1/cancel(sinx+cosx)#

#=1/(sinxcosx)#

#=1/sinx*1/cosx#

#=cscx*1/cosx#

#=cscx/cosx#

#:. = #Right Side