Question #e0579

1 Answer
Nov 5, 2016

Answer:

For angles #0 <= theta <= 360°#

#theta = 180° - 45° = 135°#
or
#theta = 180°+45° =225°#

Explanation:

#sec^-1 = (-sqrt2)/1 = h/o#

The root angle is #45°# - based on an isosceles triangle with sides in the ratio: #1 :1 :sqrt2#

Sec is negative in the 2nd and 4th quadrants.

So for angles #0 <= theta <= 360°#

#theta = 180° - 45° = 135°#
or
#theta = 180°+45° =225°#