# How do you solve the inverse trig function cos^-1 (-sqrt2/2)?

Mar 7, 2018

$\frac{3 \pi}{4}$
Find $\arccos \left(- \frac{\sqrt{2}}{2}\right)$.
$\cos x = - \frac{\sqrt{2}}{2}$
$x = \frac{3 \pi}{4}$