Question #8252f

1 Answer
Nov 6, 2016

Answer:

depends on which logs you use.

Explanation:

#log(2^(x^3))# is the same as #x^3log(2)#

so we end up with:#" "x^3log(2)=6#

#=>x^3=6/log(2)#

#x= root(3)(6/log(2))#

The value of #x# will vary depending on what type of logs you use.

The usual is either #log_10" or "log_e# where #log_e# is normally written as ln

#x= root(3)(6/log_10(2)) ~~2.7113# to 4 decimal places

#x= root(3)(6/ln(2))~~2.0533# to 4 decimal places