# Question #76f5c

Nov 10, 2016

First, it is a concept of VSEPR (Valence Shell Electron Pair Repulsion Theory) .

#### Explanation:

Hydronium ion is $\textcolor{red}{{\left[{H}_{3} O\right]}^{+}}$.
So, here the central atom is Oxygen$\left(O\right)$.

Since, there is $+ v e$ charge on the entire ion, so it is better to consider the $+ v e$ charge to be on $O$ atom.

Now, $\textcolor{red}{{O}^{+}}$ has $5$ valence electrons. Out of 5 electrons, 3 will be shared by the three $H$ atoms and other two electrons form one lone pair.

So, In total, there are $\textcolor{b l u e}{3}$ bond pairs and $\textcolor{b l u e}{1}$ lone pair on $O$ atom.

So, it's distribution is TETRAHEDRAL , and the shape is Trigonal PYRAMIDAL in order to allow least possible repulsions.

So, lewis structure and shape of Hydronium ion is :

Hope it Helps :)