Question

What mass of `"calcium oxide"` results from the decomposition of a `200*g` mass of `"calcium carbonate"`?

Answer 1

We need (i), a stoichiometrically balanced equation.........

Explanation:

`CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr`

And thus (ii) moles of limestone are equivalent to the molar quantity of calcium oxide:

`"Moles of calcium carbonate"` `=` `(200*g)/(100*g*mol^-1)=2*mol.`

And thus an equivalent quantity of calcium oxide are left, i.e.

`2*molxx56*g*mol^-1=??g`