What mass of #"calcium oxide"# results from the decomposition of a #200*g# mass of #"calcium carbonate"#?

1 Answer
Jan 18, 2017

Answer:

We need (i), a stoichiometrically balanced equation.........

Explanation:

#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#

And thus (ii) moles of limestone are equivalent to the molar quantity of calcium oxide:

#"Moles of calcium carbonate"# #=# #(200*g)/(100*g*mol^-1)=2*mol.#

And thus an equivalent quantity of calcium oxide are left, i.e.

#2*molxx56*g*mol^-1=??g#