What mass of $"calcium oxide"$ results from the decomposition of a $200*g$ mass of $"calcium carbonate"$ ?

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Answer 1 · 2017-01-18T06:44:50

We need (i), a stoichiometrically balanced equation.........

$CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr$

And thus (ii) moles of limestone are equivalent to the molar quantity of calcium oxide:

$"Moles of calcium carbonate"$ $=$ $(200*g)/(100*g*mol^-1)=2*mol.$

And thus an equivalent quantity of calcium oxide are left, i.e.

$2*molxx56*g*mol^-1=??g$

What mass of "calcium oxide""calcium oxide" results from the decomposition of a 200*g200*g mass of "calcium carbonate""calcium carbonate"?