# Question #f8416

Jan 12, 2017

He is running at 4.5 m/s

#### Explanation:

Since kinetic energy is $\frac{1}{2} m {v}^{2}$, we can find his speed as follows:

$K = \frac{1}{2} m {v}^{2}$

${v}^{2} = 2 \frac{K}{m}$

$v = \sqrt{\frac{2 K}{m}} = \sqrt{\frac{\left(2\right) \left(734\right)}{72.5}} = 4.5 \frac{m}{s}$