# If the sum of the first three terms of a geometric sequence is #52#, and the common ratio is #3#, what are the first and sixth terms?

##### 1 Answer

Aug 30, 2017

#### Explanation:

I'll answer the first question and leave the other ones up to other contributors.

The formula for the sum of the first

#s_n = (a(1- r^n))/(1- r)#

We know the sum of the first

#52 = (a(1 - 3^3))/(1 - 3)#

Solving, we get:

#52(-2) = a(1- 27)#

#-104 = -26a#

#a = 4#

Recall that the nth term of a geometric sequence is given by

Hopefully this helps!