Question #c8eb0

1 Answer
Nov 18, 2016

Answer:

You have been given a series of stoichiometric equations.....

Explanation:

For #a.# #2Al+3Cl_2 rarr 2AlCl_3#

Two equivalents, 2 moles if you like, of aluminum metal react with 3 equiv of dichlorine gas to give 2 equiv aluminum trichloride.

You starting conditions propose that you have #3.6# mol of aluminum metal, and #5.3# mol of #Cl_2# gas. Clearly (?), there is insufficient chlorine gas for all the metal to react (given the stoichiometry, 3.6 mol of metal require #5.4# mol of bimolecular chlorine gas, and you only have #5.3# mol of #Cl_2# gas.

And thus here, #Cl_2# gas is the limiting reagent, which governs the extent of the reaction. At most #5.3xx2/3*mol# aluminum chloride can be generated given the limiting quantity of chlorine.

I am reluctant to do the remaining problems, because I think you should work thru them yourself. You have been given balanced chemical equations that describe the equivalence, the stoichiometry. Make an attempt, and someone here will help you.