Question

Question #70ca9

Answer 1

`RHS=cosY/(1-sinY)`

`=(cosY(1+sinY))/((1+sinY)(1-sinY))`

`=(cosY(1+sinY))/(1-sin^2Y)`

`=(cosY(1+sinY))/cos^2Y`

`=(1+sinY)/cosY`

`=1/cosY+sinY/cosY`

`=secY+tanY=LHS`

Proved