How do you expand #(x-4)(2x+3)# to get a trinomial?

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Answer 1 · 2016-11-20T23:30:33

#2x^2 - 5x - 12#

I may be wrong, but did you mean "expand" instead of "factor"?

I went with "expand" as you requested a trinomial.

#(x - 4)(2x + 3)#

FOIL time!!!

#2x^2 + 3x - 8x - 12#
#2x^2 - 5x - 12#

Answer 2 · 2016-11-20T23:46:23

#(x-4)(2x+3)=2x^2-5x-12#

You need to multiply the two binomials to get a trinomial. Use the FOIL method, which shows the order of multiplication.

#(x-4)(2x+3)=x*2x+x*3+(-4*2x)+(-4*3)#

#(x-4)(2x+3)=2x^2+3x-8x-12#

#(x-4)(2x+3)=2x^2-5x-12#