# Question #19a2a

##### 1 Answer
Nov 27, 2016

The component of the gravitational pull on the block along the inclined plane

$F = m g \sin \theta$

As there is no frictional force the acceleration of the block will be

$a = \frac{F}{m} = g \sin \theta = 10 \times \sin {22}^{\circ} m {s}^{-} 2 \approx 3.74 m {s}^{-} 2$