Question

How do you evaluate `intsin(2x)/sin(x)dx`?

Answer 1

Use `sin(2x)=2sin(x)cos(x)`.

Explanation:

What you need is a double angle trig. identity. Namely, `sin(2x)=2sin(x)cos(x)` will do the trick.

`intsin(2x)/sin(x)dx=>int(2sin(x)cos(x))/sin(x)dx`

Now you can get `sin(x)` to cancel, leaving you with:

`int2cos(x)dx=2sin(x)+C`

Good luck!