# Given Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g), how do we calculate the molar equivalence?

Nov 27, 2016

You have a stoichiometrically balanced equation, and a molar quantity of ferric oxide.

#### Explanation:

$F {e}_{2} {O}_{3} \left(s\right) + 3 C O \left(g\right) \rightarrow 2 F e \left(s\right) + 3 C {O}_{2} \left(g\right)$

And thus 1 equiv ferric oxide reacts with 3 equiv carbon monoxide to give 2 equiv iron, and 3 equiv carbon dioxide.

$A .$ There are $1.5 \times {10}^{3}$ mol $\text{ferric oxide}$, and by the given stoichiometry $3.0 \times {10}^{3}$ mol iron metal will be produced.

$B .$ $4.5 \times {10}^{3}$ mol carbon dioxide will be evolved.

$C .$ $4.5 \times {10}^{3}$ mol carbon monoxide will be required for the reduction.

All of these answers are pretty straightforward, and do not even require a calculator. Writing the stoichiometric equation, so we can see the equivalence, is absolutely vital.