Given #Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g)#, how do we calculate the molar equivalence?

1 Answer
Nov 27, 2016

Answer:

You have a stoichiometrically balanced equation, and a molar quantity of ferric oxide.

Explanation:

#Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g)#

And thus 1 equiv ferric oxide reacts with 3 equiv carbon monoxide to give 2 equiv iron, and 3 equiv carbon dioxide.

#A.# There are #1.5xx10^3# mol #"ferric oxide"#, and by the given stoichiometry #3.0xx10^3# mol iron metal will be produced.

#B.# #4.5xx10^3# mol carbon dioxide will be evolved.

#C.# #4.5xx10^3# mol carbon monoxide will be required for the reduction.

All of these answers are pretty straightforward, and do not even require a calculator. Writing the stoichiometric equation, so we can see the equivalence, is absolutely vital.