Question

Given `Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g)`, how do we calculate the molar equivalence?

Answer 1

You have a stoichiometrically balanced equation, and a molar quantity of ferric oxide.

Explanation:

`Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g)`

And thus 1 equiv ferric oxide reacts with 3 equiv carbon monoxide to give 2 equiv iron, and 3 equiv carbon dioxide.

`A.` There are `1.5xx10^3` mol `"ferric oxide"`, and by the given stoichiometry `3.0xx10^3` mol iron metal will be produced.

`B.` `4.5xx10^3` mol carbon dioxide will be evolved.

`C.` `4.5xx10^3` mol carbon monoxide will be required for the reduction.

All of these answers are pretty straightforward, and do not even require a calculator. Writing the stoichiometric equation, so we can see the equivalence, is absolutely vital.