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Answer 1 · 2016-11-28T13:09:35

Given
#"wt of sample in air"=295N#

#"wt of sample in alcohol"=200N#

#"sp.gravity of alcohol"=0.7#

#"density of alcohol"=0.7gcm^-3=(0.7*10^-3kg)/(10^-6m^3)=700kgm^-3#

Now wt of displaced alcohol by the sample

#="Its wt in air - wt in alcohol"#

#=295-200=95N#

a) Now if # vm^3# be the volume of the sample,then the weight of displaced alcofol by the sample

#=vxx700xx9.8N#

So #vxx700xx9.8=95#

#=>v=95/(700xx9.8)~~0.01385m^3#

b) Density of the material

#="mass"/"volume"#

#=(295/9.8)/(95/(700xx9.8))m^3#

#=(295xx700)/95~~2173.7kgm^-3#