Question #228d8

1 Answer
sente
Nov 29, 2016

bar(27+16i) = 27-16i

Explanation:

The complex conjugate of a complex number a+bi, denoted bar(a+bi), is given by bar(a+bi) = a-bi.

In the given case, we have a=27 and b=16, so

bar(27+16i) = 27-16i

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