Question

Question #228d8

Answer 1

`bar(27+16i) = 27-16i`

Explanation:

The complex conjugate of a complex number `a+bi`, denoted `bar(a+bi)`, is given by `bar(a+bi) = a-bi`.

In the given case, we have `a=27` and `b=16`, so

`bar(27+16i) = 27-16i`