Given #cosA=5/13 and sinA=12/13#
Now when #theta=pi+A#
#sintheta=sin(pi+A)=-sinA=-12/13#
#costheta=cos(pi+A)=-cosA=-5/13#
when #theta=2pi-A#
#sintheta=sin(2pi-A)=-sinA=-12/13#
#costheta=cos(2pi-A)=cosA=5/13#
when #theta=3pi-A#
#sintheta=sin(3pi-A)=sinA=12/13#
#costheta=cos(3pi-A)=-cosA=-5/13#
when #theta=pi/2+A#
#sintheta=sin(pi/2+A)=cosA=5/13#
#costheta=cos(pi/2+A)=-sinA=-12/13#