Question #325c7

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Answer 1 · 2017-06-28T14:51:14

#sf([HCl]=0.2011color(white)(x)"mol/l")#

Start with the equation:

#sf(Na_2CO_(3(s))+2HCl_((aq))rarr2NaCl_((aq))+CO_(2(g))+H_2O_((l)))#

This tells us that 1 mole #sf(Na_2CO_3)# reacts with 2 moles #sf(HCl)#.

The no. moles #sf(Na_2CO_3)# is given by:

#sf(n_(Na_2CO_3)=m/M_r=0.2816/105.99=0.0026585)#

#:.##sf(n_(HCl)=0.00265685xx2=0.0053137)#

#sf([HCl]=n/v=0.0053137/0.02642=0.2011color(white)(x)"mol/l")#