If the volume of an ideal gas at "350 torr" of pressure and 25^@ "C" is "450 L", at what temperature is its volume "420 L" and pressure "830 torr" in a sealed balloon?

Dec 8, 2016

386.6 degrees C

Explanation:

$\frac{{V}_{1} \times {P}_{1}}{T} _ 1 = \frac{{V}_{2} \times {P}_{2}}{T} _ 2$

${V}_{1} = 450$
${P}_{1} = 350$
${T}_{1} = 273 + 25 = 298$ temperature must be calculated in degrees K or absolute zero.

${V}_{2} = 420$
${P}_{2} = 830$
 T_2 = unknown ?

putting these values into the equation gives

$\frac{450 \times 350}{298} = \frac{420 \times 830}{T} _ 2$ Solving for ${T}_{2}$ gives

${T}_{2} = \frac{420 \times 830 \times 298}{450 \times 350}$ solving gives

#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives

${T}_{2} = 386.6$