If the volume of an ideal gas at #"350 torr"# of pressure and #25^@ "C"# is #"450 L"#, at what temperature is its volume #"420 L"# and pressure #"830 torr"# in a sealed balloon?

1 Answer

Answer:

386.6 degrees C

Explanation:

# (V_1 xx P_1)/T_1 = (V_2 xx P_2)/T_2#

# V_1 = 450#
# P_1 = 350#
# T_1 = 273 + 25 = 298 # temperature must be calculated in degrees K or absolute zero.

# V_2 = 420#
# P_2 = 830#
# T_2 = unknown ?#

putting these values into the equation gives

# (450 xx 350)/298 = (420 xx 830)/T_2# Solving for #T_2# gives

#T_2 = (420 xx 830 xx 298)/ (450 xx 350)# solving gives

#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives

#T_2 = 386.6 #