# Question 74c9b

Dec 9, 2016

You need 6 liters of pure antifreeze and 3 liters of 10%

#### Explanation:

Let $v =$volume of pure anti freeze

Then $9 - v =$volume of 10% anti freeze mixture

You write an equation , with respect to the quantity of anti freeze

v*100%+(9-v)*10%=9*70%#

So,

$v + 0.1 \left(9 - v\right) = 9 \cdot 0.7 = 6.3$

$v + 0.9 - 0.1 v = 6.3$

$0.9 v = 5.4$

$v = \frac{5.4}{0.9} = 6$

Volume of pure anti feeze $= 6$ liters

Volume of 10 % anti freeze $= 3$liters