How do you divide $1 \frac{2}{3}$ $1 2/3$ by $2 \frac{3}{4}$ $2 3/4$ ?

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How do you divide $1 \frac{2}{3}$ $1 2/3$ by $2 \frac{3}{4}$ $2 3/4$ ?

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Answer 1 · 2016-12-07T04:09:15

$\frac{20}{33}$ $20/33$

Explanation:

First, we need to convert each mixed fraction to an improper fraction

$1 \frac{2}{3} = (\frac{3}{3} \times 1) + \frac{2}{3} \to \frac{3}{3} + \frac{2}{3} \to \frac{5}{3}$ $1 2/3 = (3/3 xx 1) + 2/3 -> 3/3 + 2/3 -> 5/3$

$2 \frac{3}{4} \to (\frac{4}{4} \times 2) + \frac{3}{4} \to \frac{8}{4} + \frac{3}{4} \to \frac{11}{4}$ $2 3/4 -> (4/4 xx 2) + 3/4 -> 8/4 + 3/4 -> 11/4$

Now we can write the division problem as

$\frac{\frac{5}{3}}{\frac{11}{4}}$ $(5/3)/(11/4)$

The rule for dividing fractions is:

$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}$ $color(red)((a/b)/(c/d) = (a*d)/(b*c))$

We can use this rule to divide and solve our problem:

$\frac{5 \cdot 4}{3 \cdot 11}$ $(5*4)/(3*11)$

$\frac{20}{33}$ $20/33$

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