How do you solve: #6m + 2 < 10#?

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Answer 1 · 2016-12-07T14:28:53

#m < 4/3#

First, isolate the #m# term on one side of the inequality while keeping the inequality balanced:

#6m + 2 - color(red)(2) < 10 - - color(red)(2)#

#6m + 0 < 8#

#6m < 8#

Now solve for #m# while keeping the inequality balanced:

#(6m)/color(red)(6) < 8/color(red)(6)#

#(color(red)(cancel(color(black)(6)))m)/cancel(color(red)(6)) < (2/2) * (4/3)#

#m < 1* 4/3#

#m < 4/3#