Question #739a4
1 Answer
Dec 11, 2016
Explanation:
# = int (sin^2x-cos^2x) dx#
# = int -cos(2x) dx#
Substitute
# = -1/2 sin(2x) +C#
# = int (sin^2x-cos^2x) dx#
# = int -cos(2x) dx#
Substitute
# = -1/2 sin(2x) +C#