# Question #75d2f

Dec 16, 2016

the yield is 80%, as you say.

#### Explanation:

You start by showing that 0.100 mol ${C}_{8} {H}_{18}$ should yield 0.80 mol of $C {O}_{2}$, becaus the equation shows the ratio between these to is 2 to 16 or 1 to 8.

0.80 mol of $C {O}_{2}$ would have a mass of 0.8 x 44 = 35.2 g

Because the yield was only 28.16 g, rather than 352.g, the percentage yield is

$\frac{28.16}{35.2}$ x $100$ = 80% (to two digits)