# Question #a0657

Dec 12, 2017

It’s D ($m \setminus {s}^{2}$)

#### Explanation:

To find an acceleration we take a change in velocity and divide it by time, so acceleration must have units of velocity per unit time.

Velocity is defined as a change in distance divided by a change in time, so it will have units of distance per unit time.

Thus acceleration has units of m/s $\div$ s = $\frac{m}{s} ^ 2$ or $m {s}^{-} 2$

OK with that?