# Question #ccc07

##### 2 Answers

#### Explanation:

The standard form of an equation of this type is

But, in this question, we need to take

To do this, subtract

#y-y=1/2x+3-y#

#1/2x-y+3=0#

Now, we have to convert

#cancel(2)^1xx1/(cancel(2))x-2xxy+2xx3=2xx0#

#=>x-2y+6=0#

This is the standard form of the equation.

#### Explanation:

The standard form for a linear equation is:

Therefore, we must multiply each side of the given equation by

Now we can isolate the