Question

At `95.0^@"C"`, a sample of gas has a volume of `"1.55 mL"`. What will the volume be if the gas is cooled to `0.2^@"C"`?

Answer 1

The final volume will be `"1.15 mL"`.

Explanation:

Your question involves Charles' law, which states that the volume of a gas is directly proportional to its Kelvin temperature, with pressure and mass remaining constant. This means that if the volume increases, the temperature will also increase, and vice versa.

Equation

`V_1/T_1=V_2/T_2`, where `V` is volume, and `T` is temperature in Kelvins.

Known
`V_1="1.55 mL"`
`T_1="95.0"^@"C"+273.15=368.2 "K"`
`T_2="0.2"^@"C"+273.15=273.4 "K"`

Unknown
`V_2`

Solution
Rearrange the equation to isolate `V_2`. Plug in the known values and solve.

`V_2=(V_1T_2)/T_1`

`V_2=(1.55"mL"xx273.4"K")/(368.2"K")="1.15 mL"`