# Question #a5af9

Dec 15, 2016

Simply multiply the $\text{molar volume}$ by the amount in $\text{moles}$.

#### Explanation:

$\text{Molar volume "xx" molar quantity}$

$= 82.4 \cdot m L \cdot \cancel{m o {l}^{-} 1} \times 250 \times {10}^{-} 3 \cdot \cancel{m o l} \cong 20 \cdot m L$

And when we do the problem dimensionally in this manner we automatically get an answer in $m L$ as required.

Dec 15, 2016

Amount of liquid octane $= 250 m m o l = 250 \times {10}^{-} 3 m o l$

Volume this octane

$= \text{no of mole"xx"molar volume}$

$= 250 \times {10}^{-} 3 m o l \times 82.4 \text{ml"/"mol}$

$= 20.6 m l$