Question #a5af9

2 Answers
Dec 15, 2016

Answer:

Simply multiply the #"molar volume"# by the amount in #"moles"#.

Explanation:

#"Molar volume "xx" molar quantity"#

#=82.4*mL*cancel(mol^-1)xx250xx10^-3*cancel(mol)~=20*mL#

And when we do the problem dimensionally in this manner we automatically get an answer in #mL# as required.

Dec 15, 2016

Amount of liquid octane #=250mmol=250xx10^-3mol#

Volume this octane

#="no of mole"xx"molar volume"#

#=250xx10^-3molxx82.4"ml"/"mol"#

#=20.6ml#